Timeout on a function call

Question

I\'m calling a function in Python which I know may stall and force me to restart the script.

How do I call the function or what do I wrap it in so that if it takes

Answer 1

The stopit package, found on pypi, seems to handle timeouts well.

I like the @stopit.threading_timeoutable decorator, which adds a timeout parameter to the decorated function, which does what you expect, it stops the function.

Check it out on pypi: https://pypi.python.org/pypi/stopit