Why won't DynamicProxy's interceptor get called for *each* virtual method call?

Question

An example explains it best :

public interface IA { 
  void foo();
  void bar();
}

public class A : IA {
  public virtual void foo(){
    Console.Write(\"foo\")         


        

Answer 1

Looks like my guess was right.

I tried the same example, only this time creating the proxy directly from the class type:

Main(){

  //proxy-ing an explicit type
  A proxy = (A) new Castle.DynamicProxy.ProxyGenerator()
                 .CreateClassProxy(new Interceptor());
  proxy.foo();

}

The result was what I expected in the first place:

Intercepted foo
foo
Intercepted bar
bar

This leads me to the following conclusion:

• when creating a proxy from an interface, it uses composition to delegate calls to the implementation
• when creating a proxy from a (class) type, it inherits from the type, so all virtual calls in the class type will call the overridden methods in the proxy.

When creating an interface proxy with an interface implementation, the generated proxy looks something like this:

class InterfaceProxy: IA { //implements interface
  IA m_impl;
  [...]

  Proxy(IA i_impl){
    m_impl = i_impl;
  }
  public void foo(){
    //overly-simplified, but you get the picture
    InvokeInterceptors("foo");

    //execution gets here when calling 'invocation.Proceed()' 
    //from the interceptor

    m_impl.foo();  //pass the execution to the implementation; 
                   //the proxy has no more control over what gets executed.

  }
  public void bar(){
    InvokeInterceptors("bar");
    m_impl.bar();
  }
}

When creating a class proxy, the code looks like this:

class ClassProxy: A { //inherits class type

  Proxy(): base() { ... }

  public override void foo(){
    InvokeInterceptors("foo");

    //execution gets here when calling 'invocation.Proceed()' 
    //from the interceptor

    base.foo();  //pass the execution to the base class 

  }
  public void bar(){
    InvokeInterceptors("bar");
    base.bar();
  }
}