Mongo C# Driver: Deserialize BsonValue

Question

I have a document in mongodb that is structured similar to this:

{
  \"_id\": \"abcdef01234\",
  \"Name\": \"Product A\",
  \"Dimensions\": [
    {
      \"Heigh         


        

Answer 1

Update:

You probably looking for include/exclude functionality. In c# driver it done so:

 // load products without array of Dimensions
MongoCursorInstance.SetFields(Fields.Exclude("Dimensions"));
//load empty product with Dimensions and _id
MongoCursorInstance.SetFields(Fields.Include("Dimensions"));

---

Why not just create class for product? In this case driver will be able to deserialize data automatically :

class Product
{
   [BsonId]
   public ObjectId Id { get; set; }

   public string Name{ get; set; }

   public List Dimensions{ get; set; }

}

var product = srv["db"]["products"].FindOneByIdAs();
var dimentions = product.Dimensions;

But if you don't want create Product class you can go this way:

BsonArray dimensionsVal = doc["Dimensions"].AsBsonArray;

var list = new List();
foreach (BsonValue value in dimensionsVal)
{
  var bsonDoc = (BsonDocument) value;
  var d = new Dimension();
  d.Height = bsonDoc["Height"];
  d.Width = bsonDoc["Width"];
  list.Add(d);
}