Call a void* as a function without declaring a function pointer

Question

I\'ve searched but couldn\'t find any results (my terminology may be off) so forgive me if this has been asked before.

I was wondering if there is an easy way to call a

Answer 1

I get awfully confused when casting to function types. It's easier and more readable to typedef the function pointer type:

void *ptr = ...;
typedef void (*void_f)(void);
((void_f)ptr)();