template specialization according to sizeof type

Question

I would like to provide a templated function, that varies its implementation (->specialization) according to the sizeof the template type.

Something similar to this (omi

Answer 1

You don't need SFINAE or type traits. Vanilla template specialization is enough. Of course it must be specialized on structs as C++(98) doesn't support function template partial specialization.

template 
struct ByteswapImpl
/*
{
  T operator()(T& swapIt) const { throw std::exception(); }
}
*/    // remove the comments if you need run-time error instead of compile-time error.
;

template 
struct ByteswapImpl {
  T operator()(T& swapIt) const { return _byteswap_ushort (swapIt); }
};

// ...

template 
T byteswap(T& swapIt) { return ByteswapImpl()(swapIt); }