[removed] pass function as a parameter to another function, the code gets called in another order then i expect

Question

i want to pass a function to another function as a parameter.

I want to do that because the latter function calls an async Jquery method and AFTER that gives a result ba

Answer 1

$('#AddThirdParty').click(function() {
    var func = new function() {
        alert('1');
        alert('2');
        alert('3');
    }
    alert('4');
    LoadHtml(func);
    alert('5');
});
function LoadHtml(funcToExecute) {
    //load some async content
    funcToExecute;
}

The new keyword creates an object from the function. This means the function (which is anonymous) gets called immediatly. This would be the same as

var foo = function() {
    alert("1");
    alert("2");
    alert("3");
}
var func = new foo();

This means your creating a new object (not a function!) and inside the constructor your alert 1,2,3. Then you alert 4. Then you call LoadHtml which does nothing, then you alert 5.

As for

funcToExecute;

The funcToExecute is just a variable containing a function. It actually needs to be executed.