checking integer overflow in python

Question

class Solution(object):
    def reverse(self, x):
        \"\"\"
        :type x: int
        :rtype: int
        \"\"\"
        negative = False
        if(x < 0):
          


        

Answer 1

class Solution:
    def reverse(self, x: int) -> int:

        split = [i for i in str(x)]
        split = split[::-1]
        final = ''

        
        if split[-1]=='-':
            final += '-'
            
            for i in split[0:-1]:
                print(i)
                final+=i
        else:
            
            for i in split[0:]:
                final+=i
                
        final = int(final)
        
        if(abs(final) > (2 ** 31 - 1)):
                return 0
                
        return(final)