checking integer overflow in python

Question

class Solution(object):
    def reverse(self, x):
        \"\"\"
        :type x: int
        :rtype: int
        \"\"\"
        negative = False
        if(x < 0):
          


        

Answer 1

I guess some thing light weight like below could perhaps achieve the same logic, For someone else looking , the main overflow check after reversed 32 bit int is

if(abs(n) > (2 ** 31 - 1)):
                    return 0    

Full code below

def reverse(self, x):

            neg = False
            if x < 0:
                neg = True
                x = x * -1

            s = str(x)[::-1]
            n = int(s)
            if neg:
                n = n*-1
            if(abs(n) > (2 ** 31 - 1)):
                return 0
            return n