What is scheme's equivalent of tuple unpacking?

Question

In Python, I can do something like this:

t = (1, 2)
a, b = t

...and a will be 1 and b will be 2. Suppose I have a list \'(1 2) in

Answer 1

This works in Racket if you don't want to bring in the match dependency:

From a list:

(let-values ([(a b c) (apply values '(1 2 3))])
  (+ a b c))

Or directly from a values expression:

(let-values ([(a b c) (values 1 2 3)])
  (+ a b c))