python calling a module that uses argparser

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傲寒
傲寒 2021-02-05 07:23

This is probably a silly question, but I have a python script that current takes in a bunch of arguements using argparser and I would like to load this script as a module in ano

3条回答
  •  情歌与酒
    2021-02-05 07:59

    The first argument to parse_args is a list of arguments. By default it's None which means use sys.argv. So you can arrange your script like this:

    import argparse as ap
    
    def main(raw_args=None):
        parser = ap.ArgumentParser(
            description='Gathers parameters.')
        parser.add_argument('-f', metavar='--file', type=ap.FileType('r'), action='store', dest='file',
                            required=True, help='Path to json parameter file')
        parser.add_argument('-t', metavar='--type', type=str, action='store', dest='type',
                            required=True, help='Type of parameter file.')
        parser.add_argument('-g', metavar='--group', type=str, action='store', dest='group',
                            required=False, help='Group to apply parameters to')
        # Gather the provided arguements as an array.
        args = parser.parse_args(raw_args)
        print(vars(args))
    
    
    # Run with command line arguments precisely when called directly
    # (rather than when imported)
    if __name__ == '__main__':
        main()
    

    And then elsewhere:

    from first_module import main
    
    main(['-f', '/etc/hosts', '-t', 'json'])
    

    Output:

    {'group': None, 'file': <_io.TextIOWrapper name='/etc/hosts' mode='r' encoding='UTF-8'>, 'type': 'json'}
    

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