Perl, convert hash to array

Question

If I have a hash in Perl that contains complete and sequential integer mappings (ie, all keys from from 0 to n are mapped to something, no keys outside of this), is there a mean

Answer 1

An easy way is to do @array = %hash

For example,

my %hash = (
    "0"  => "zero",
    "1" => "one",
    "2"  => "two",
    "3"  => "three",
    "4"  => "four",
    "5"  => "five",
    "6"  => "six",
    "7"  => "seven",
    "8"  => "eight",
    "9"  => "nine",
    "10"  => "ten",
);

my @array = %hash;

print "@array"; would produce the following output,

3 three 9 nine 5 five 8 eight 2 two 4 four 1 one 10 ten 7 seven 0 zero 6 six