How to write a binary file using Bash?

Question

My problem is that I need to create a file with this exact bytes: 48, 00, 49, 00.

I cannot use C, perl, other scripting language (the target is an embedded

Answer 1

POSIX AWK standard says that passing a 0 to AWK's printf with %c format can result in unspecified behaviour. However... POSIX echo also is very limited, and though octal and hexadecimal specifiers (and -n) will work on GNU echo and BASH built-in... They may not work everywhere. To maximize the chance that you get consistent behaviour on all POSIX systems, it is better to use the shell command line's printf than either of these.

$ printf '\060\000\061\000' | od -An -tx1
 30 00 31 00

This looks odd to me though... You may be wanting to output 0x48, 0x00, 0x49, 0x00 -- which looks like a pretty pilot number in octal:

$ printf '\110\000\111\000' | od -An -tx1
 48 00 49 00