Initialize a constant sized array in an initializer list

Question

I\'ve got a situation which can be summarized in the following:

class Test
{

    Test();

    int MySet[10];

};

is it possible to initialize

Answer 1

"I understand that Set is just a pointer to the static array of 10 integers"

No, that's wrong: it's an array, not a pointer.

You can still initialize it in the constructor's initializer list.

For a compiler that doesn't support C++11 curly braces initialization (Visual C++ version 11 and earlier comes to mind) you'll have to jump through some hoops though, as shown below:

#include 
#include 
using namespace std;

#define CPP11
#if defined( _MSC_VER )
#   if (_MSC_VER <= 1700)
#       undef CPP11
#   endif
#endif

#ifdef CPP11
class Cpp11
{
private:
    int set_[10];

public:
    Cpp11()
        : set_{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }
    {}

    int foo() const { return set_[3]; }
};
#endif

class Cpp03
{
private:
    struct IntArray10 { int values[10]; };
    IntArray10 set_;

    static IntArray10 const& oneToTen()
    {
        static IntArray10 const values =
            { {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} };
        return values;
    }

public:
    Cpp03()
        : set_( oneToTen() )
    {}

    int foo() const { return set_.values[3]; }
};

int main()
{}

Instead of using raw arrays, though, use std::vector and C+++11 std::array, both of which are supported even by Visual C++ 11.