Java: extending a class and implementing an interface that have the same method

Question

Probably the following cannot be done (I am getting a compilation error: \"The inherited method A.doSomthing(int) cannot hide the public abstract method in B\"):

Answer 1

The method doSomethis() is package-private in class A:

public class A {
    int doSomthing(int x) { // this is package-private
        return x;
    }
}

But it is public in the interface B:

public interface B {
    int doSomthing(int x); // this here is public by default
}

Compiler is taking the doSomething() inherited by C from A which is package-private as the implementation of the one in B which is public. That's why it's complaining -

"The inherited method A.doSomthing(int) cannot hide the public abstract method in B"

Because, while overriding a method you can not narrow down the access level of the method.

Solution is easy, in class C -

@Override
public int doSomthing(int x) {
    // ...
}