Can a lambda capturing nothing access global variables?

Question

int n;    
int main()
{
    [](){ n = 0; }(); // clang says \"ok\"

    int m;
    [](){ m = 0; }(); // clang says \"not ok\"
}

I just wonder:

Answer 1

Global, static and const variables are accessed by default:

#include 

int n;    
int main()
{
    [](){ n = 10; }();
    std::cout << n << std::endl;
    static int m = 1;
    [](){ m = 100; }();
    std::cout << m << std::endl;
    const int l = 200;
    [](){ std::cout << l << std::endl; }();
}