If I write a method accepting a parameter which derives from a BaseClass
(or an interface), as far as I know there are two ways to achieve that:
voi
As was said, it matters only once you get a return value. Consider these cases:
BaseClass MyMethod(BaseClass)
DervivedClass temp = new DervivedClass();
//Error. My Method always returns a BaseClass. No implicit casting available
temp = MyMethod(temp);
Compare it to this:
T MyMethod
DervivedClass temp = new DerivedClass();
temp = MyMethod(temp);
Strong Typification is one of the best friends you have in .NET. Embrace it. Never try to avoid it. The opposite would be cases like we have in PHP and JavaScript: http://www.sandraandwoo.com/2015/12/24/0747-melodys-guide-to-programming-languages/