The case is simple - I\'ve got a following object:
Object {1: false, 2: true, 3: false, 4: false, 5: false, 6: false, 7: false, 8: true, 12: false, 13: false, 14
Heres a way to do it without using any libraries in ES6
let z = {2: true, 3:false, 8:true, 9:false, 10: false} Array.from(new Set(Object.keys(z).map(function(k){if(z[k]){return k}}))).filter(f=>f)
and out you get [2, 8]
[2, 8]