How is ArrayOutOfBoundsException possible in String.valueOf(int)?

Question

Why does this code sometimes produce ArrayOutOfBoundsException? How is that even possible for String.valueOf(int)?

public static String ipToString(B         


        

Answer 1

I am leaving the code snippet here, as it still ought to be run faster than the original code - at a cost of memory - but be advised it doesn't actually fix the problem.

private static final String[] STRING_CACHE = new String[256];

static {
  for(int i = 0; i <= 255; i++) {
    STRING_CACHE[i] = String.valueOf(i);
  }
}

public static String ipToString(ByteString bs) {
  if (bs == null || bs.isEmpty()) {
    return null;
  } else {
    StringBuilder sb = new StringBuilder();
    boolean started = false;
    for (Byte byt : bs) {
      if (started) {
        sb.append(".");
      }
      sb.append(STRING_CACHE[byt & 0xFF]);
      started = true;
    }

    return sb.toString();
  }
}