Can a lambda expression be passed as function pointer?

Question

I am trying to pass a lambda expression to a function that takes a function pointer, is this even possible?

Here is some sample code, I\'m using VS2010:

Answer 1

This works in VS2010:

template
void* getcodeptr(const FunctorT& f) {
  auto ptr = &FunctorT::operator();
  return *(void**)&ptr;
} 

void main() {
  auto hello = [](char* name){ printf("hello %s\n", name); };
  void(*pfn)(char*) = (void(*)(char*)) getcodeptr(hello);
  pfn("world");
}