What is the best way to export an object literal with ES6/2015?

Question

Seemingly a very simple task...

export default function() {
    return {
        googleClientID:\'xxxx\'
    }
}

Is it the best way to export o

Answer 1

@madox2 's and @void 's answer may be some kind of common misunderstanding.

I just ran into a similar problem while issuing a PR to DefinitelyTyped -- #18725. The typescript compiler complains about the generated files.

A example should be:

// ...
import zip from "./zip";
import zipObject from "./zipObject";
import zipObjectDeep from "./zipObjectDeep";
import zipWith from "./zipWith";

export default {
  // ...
  zip,
  zipObject,
  zipObjectDeep,
  zipWith
};

At the first glance, i didn't think its my problem. Because i just copy the code from lodash-es. But then i can't find any simple approach to remove the errors.

So I go to the spec for answer. Wow, the spec doesn't talk about default export of an object, if I read it right.

Conclusion:

The follow is spec-respected:

export { googleClientID:'xxxx' }

---

Just found some more references:

• https://medium.com/@timoxley/named-exports-as-the-default-export-api-670b1b554f65#a279
• https://medium.com/@rauschma/note-that-default-exporting-objects-is-usually-an-anti-pattern-if-you-want-to-export-the-cf674423ac38