unsigned int (c++) vs uint (c#)

Question

Following is the c# code:

   static void Main(string[] args)
    {
        uint y = 12;
        int x = -2;
        if (x > y)
            Console.WriteLine(\         


        

Answer 1

In C++, when you compare an unsigned int and a signed int, the signed int is converted to unsigned int. Converting a negative signed int to an unsigned int is done by adding UINT_MAX + 1, which is larger than 12 and hence the result.

In C#, if you are getting the opposite result then it means that in C# both the expressions are being converted to signed int signed long (long or System.Int64)¹ and then compared.

In C++, your compiler must have given you the warning:

warning: comparison between signed and unsigned integer expressions

Rule:
Always take warnings emitted by the compiler seriously!

^{1 As rightly pointed out by svick in comments.}