How to convert an arbitrary large integer from base 10 to base 16?

Question

The program requires an input of an arbitrary large unsigned integer which is expressed as one string in base 10. The outputs is another string that expresses the integer in bas

Answer 1

1. Allocate an array of integers, number of elements is equal to the length of the input string. Initialize the array to all 0s.

   This array of integers will store values in base 16.

2. Add the decimal digits from the input string to the end of the array. Mulitply existing values by 10 add carryover, store new value in array, new carryover value is newvalue div 16.

   carryover = digit;
   for (i = (nElements-1); i >= 0; i--)
   {
       newVal = array[index] * 10) + carryover;
       array[index] = newval % 16;
       carryover = newval / 16;
   }
   

3. print array, start at 0th entry and skip leading 0s.

---

Here's some code that will work. No doubt there are probably a few optimizations that could be made. But this should suffice as a quick and dirty solution:

#include 
#include 
#include 
#include "sys/types.h"

char HexChar [16] = { '0', '1', '2', '3', '4', '5', '6', '7',
                      '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };

static int * initHexArray (char * pDecStr, int * pnElements);

static void addDecValue (int * pMyArray, int nElements, int value);
static void printHexArray (int * pHexArray, int nElements);

static void
addDecValue (int * pHexArray, int nElements, int value)
{
    int carryover = value;
    int tmp = 0;
    int i;

    /* start at the bottom of the array and work towards the top
     *
     * multiply the existing array value by 10, then add new value.
     * carry over remainder as you work back towards the top of the array
     */
    for (i = (nElements-1); (i >= 0); i--)
    {
        tmp = (pHexArray[i] * 10) + carryover;
        pHexArray[i] = tmp % 16;
        carryover = tmp / 16;
    }
}

static int *
initHexArray (char * pDecStr, int * pnElements)
{
    int * pArray = NULL;
    int lenDecStr = strlen (pDecStr);
    int i;

    /* allocate an array of integer values to store intermediate results
     * only need as many as the input string as going from base 10 to
     * base 16 will never result in a larger number of digits, but for values
     * less than "16" will use the same number
     */

    pArray = (int *) calloc (lenDecStr,  sizeof (int));

    for (i = 0; i < lenDecStr; i++)
    {
        addDecValue (pArray, lenDecStr, pDecStr[i] - '0');
    }

    *pnElements = lenDecStr;

    return (pArray);
}

static void
printHexArray (int * pHexArray, int nElements)
{
    int start = 0;
    int i;

    /* skip all the leading 0s */
    while ((pHexArray[start] == 0) && (start < (nElements-1)))
    {
        start++;
    }

    for (i = start; i < nElements; i++)
    {
        printf ("%c", HexChar[pHexArray[i]]);
    }

    printf ("\n");
}

int
main (int argc, char * argv[])
{
    int i;
    int * pMyArray = NULL;
    int nElements;

    if (argc < 2)
    {
        printf ("Usage: %s decimalString\n", argv[0]);
        return (-1);
    }

    pMyArray = initHexArray (argv[1], &nElements);

    printHexArray (pMyArray, nElements);

    if (pMyArray != NULL)
        free (pMyArray);

    return (0);
}