How to find if two numbers are consecutive numbers in gray code sequence

Question

I am trying to come up with a solution to the problem that given two numbers, find if they are the consecutive numbers in the gray code sequence i.e., if they are gray code neig

Answer 1

You can check if two numbers differ by one bit or not as follows. In this method, difference in the length of binary numbers are taken care of. Eg, the output for 11 (1011) and 3 (11) will be returned as true. Also, this does not solve the second criteria for Gray code adjacency. But if you only want to check if the numbers differ by one bit, the code below will help.

class Graycode{
    public static boolean graycheck(int one, int two){
        int differences = 0;
        while (one > 0 || two > 0){
            // Checking if the rightmost bit is same
            if ((one & 1) != (two & 1)){
                differences++;
            }
            one >>= 1;
            two >>= 1;
        }
        return differences == 1;
    }
    public static void main(String[] args){
        int one = Integer.parseInt(args[0]);
        int two = Integer.parseInt(args[1]);
        System.out.println(graycheck(one,two));
    }
}