How to find all intersections (also called the longest common substrings) of two strings and their positions in both strings?
For example, if S1=\"never\"
Well, you're saying that you can't include any library. However, Python's standard difflib contains a function which does exactly what you expect. Considering that it is a Python interview question, familiarity with difflib might be what the interviewer expected.
In [31]: import difflib
In [32]: difflib.SequenceMatcher(None, "never", "forever").get_matching_blocks()
Out[32]: [Match(a=1, b=3, size=4), Match(a=5, b=7, size=0)]
In [33]: difflib.SequenceMatcher(None, "address", "oddness").get_matching_blocks()
Out[33]: [Match(a=1, b=1, size=2), Match(a=4, b=4, size=3), Match(a=7, b=7, size=0)]
You can always ignore the last Match tuple, since it's dummy (according to documentation).