I am learning Selenium Webdriver and trying to write a simple test script.
The intent is to get the About Google
link on
The main problem is at this line:
driver.findElement(By.cssSelector("a:contains('About Google')"));
css
doesn't maintain contains()
for Selenium WD - See here.
For using contains()
you have to use Xpath.
With Xpath your locator will be:
//a[contains(text(), 'About Google')]
and for driver it will be as:
driver.findElement(By.xpath("//a[contains(text(), 'About Google')]"));
For finding links with Selenium you can use:
driver.findElement(By.linkText("your link name here"));
It is limitation of CSS selectors compare to Xpath:
BTW
For processing Xpath locators from page you able to use extension for Firefox browser:
FirePath
Xpath Checker