How can a Java lambda-expression reference itself?

Question

I found this article to be very informative in comparison of old-style functions to new Java-8 lambda-functions and parallel processing. One thing I couldn\'t quite understand w

Answer 1

Derived from @Alex's answer:

@FunctionalInterface
public interface SelfRunnable extends Runnable {
  public void run(SelfRunnable this_);

  @Override
  public default void run() {
    run(this);
  }

  public static Runnable runnable(SelfRunnable runnable) {
    return runnable;
  }
}

public interface Test {
  public static void main(String... arguments) {
    final Runnable r = SelfRunnable.runnable(this_ -> this_.run());
    r.run();
  }
}