How can a Java lambda-expression reference itself?

Question

I found this article to be very informative in comparison of old-style functions to new Java-8 lambda-functions and parallel processing. One thing I couldn\'t quite understand w

Answer 1

public class Test {
    static Runnable r;

    public static void main(String... args) {
        r = () -> r.run();
        r.run();
    }
}

The Runnable obtains a reference to itself from the field r when it is run.

You could also use a length 1 array to store the reference if you don't like adding a field.