XPath 1 query and attributes name

Question

First question: is there any way to get the name of a node\'s attributes?

Answer 1

First question: is there any way to get the name of a node's attributes?

Yes: This XPath expression (when node is the context (current) node)):

    name(@*[1])

produces the name of the first attribute (the ordering may be implementation - dependent)

and this XPath expression (when node is the context (current) node)):

    name(@*[2])

produces the name of the second attribute (the ordering may be implementation - dependent).

Second question: is there a way to get attributes and values as value pairs? The situation is the following:

I want to get all attributes where value>0 and this way: "attribute1=10".

This XPath expression (when the attribute named "attribute1" is the context (current) node)):

    concat(name(), '=', .)

produces the string:

    attribute1=value1

and this XPath expression (when the node node is the context (current) node)):

    @*[. > 0]

selects all attributes of the context node, whose value is a number, greater than 0.

In XPath 2.0 one can combine them in a single XPath expression:

    @*[number(.) > 0]/concat(name(.),'=',.)

to get (in this particular case) this result:

    attribute1=10

If you are using XPath 1.0, which is less powerful, you'll need to embed the XPath expression in a hosting language, such as XSLT. The following XSLT 1.0 thransformation :

when applied on this XML document:

Produces exactly the same result:

    attribute1=10