Python split url to find image name and extension

Question

I am looking for a way to extract a filename and extension from a particular url using Python

lets say a URL looks as follows

picture_page = \"http://dis         


        

Answer 1

>>> import re
>>> s = 'picture_page = "http://distilleryimage2.instagram.com/da4ca3509a7b11e19e4a12313813ffc0_7.jpg"'
>>> re.findall(r'\/([a-zA-Z0-9_]*)\.[a-zA-Z]*\"$',s)[0]
'da4ca3509a7b11e19e4a12313813ffc0_7'
>>> re.findall(r'([a-zA-Z]*)\"$',s)[0]
'jpg'