How do you have a NaN case in a switch statement?

Question

Since NaN === NaN evaluates to false, is it possible to add a NaN case to a switch statement?

For example, let\'s say

Answer 1

@helmus's answer is correct and is a good solution.

However, you can maintain the NaN case if you use strings:

switch(x+''){
    case "1":
    case "2":
    case "4":
        doSomething();
        break;
    case "NaN":
        doSomethingElse();
        break;
    default:
        doADifferentThing();
        break;
}