Generate a Secure Random Password in Java with Minimum Special Character Requirements

Question

How do I create a random password that meets the system\'s length and character set requirements in Java?

I have to create a random password that is 10-14 characters lo

Answer 1

I suggest using apache commons RandomStringUtils. Use something what is already done.

String characters = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789~`!@#$%^&*()-_=+[{]}\\|;:\'\",<.>/?";
String pwd = RandomStringUtils.random( 15, characters );
System.out.println( pwd );

If you are using maven

    org.apache.commons
    commons-lang3
    3.4

otherwise download jar

UPDATE Version with secure random. So matter of required characters left and can be solved as in comment, generate required parts separately and normal ones. Then join them randomly.

char[] possibleCharacters = (new String("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789~`!@#$%^&*()-_=+[{]}\\|;:\'\",<.>/?")).toCharArray();
String randomStr = RandomStringUtils.random( randomStrLength, 0, possibleCharacters.length-1, false, false, possibleCharacters, new SecureRandom() );
System.out.println( randomStr );