If I have a void pointer, how do I put an int into it?

Question

I have an array of arbitrary values, so I have defined it as an array of void pointers, so I can point to any kind of information (like int, character arrays, etc).

Answer 1

*((int*)data[0])=x;

will do it.

You might want to consider using a union. Something like this:

union myvalues
{
    int i;
    double d;
    long l;
};

You could then have

union myvalues *foo[10];
foo[0] = malloc(sizeof(union myvalues));
foo[0]->i = x;

You can also typedef the union. sizeof(union myvalues) will be the maximum of sizeof the members. So if you have int i; and char c[40] in the union, sizeof(union myvalues) will be 40. Writing to i will then overwrite the first 4 characters in c (assuming your ints are 4 bytes).