C++ return type overload hack

Question

I was bored and came up with such hack (pseudocode):

 1 struct proxy {
 2     operator int(); // int function
 3     operator double(); // double function
 4             


        

Answer 1

If you really mean something like this:

 1 struct proxy {
 2     operator long() { return refs.first; } // long has greater precision
 3     operator double() { return refs.second; } // double has greater range
 4     proxy( long const &, double const & );
 5     pair< long const &, double const & > refs;
 6 };
 7
 8 proxy function() {
 9     return proxy( numeric_limits::max() + 1,
                     double( numeric_limits::max() ) );
10 }
11 int v = function(...);
12 double u = function(...);

Then yes, I think that's cool and I would count it as a hack.

If it works. I didn't test it at all.