WPF - How to style the menu control to remove the left margin?

Question

I have added a default menu control to my user control. I need to style the menu to remove the left margin containing the space for the icon or checkbox. How can I do this?

Answer 1

Thanks for succesfull idea. For .net Framework 4.5 and VS 2012 I wrote for ContextMenu and MenuItem accordingly:

        private const double ICON_SIZE = 32;

    void ContextMenu_Loaded(object sender, System.Windows.RoutedEventArgs e)
    {
        if (_pointerControl.ContextMenu.Template != null)
        {
            System.Windows.Shapes.Rectangle r1 = _pointerControl.ContextMenu.Template.FindName("3_T", _pointerControl.ContextMenu) as System.Windows.Shapes.Rectangle;
            System.Windows.Shapes.Rectangle r2 = _pointerControl.ContextMenu.Template.FindName("4_T", _pointerControl.ContextMenu) as System.Windows.Shapes.Rectangle;
            System.Windows.Shapes.Rectangle r3 = _pointerControl.ContextMenu.Template.FindName("5_T", _pointerControl.ContextMenu) as System.Windows.Shapes.Rectangle;
            double width = Math.Max(28, ICON_SIZE+14);
            r1.Width = width;
            r2.Margin = new System.Windows.Thickness(width + 1, 2, 0, 2);
            r3.Margin = new System.Windows.Thickness(width + 2, 2, 0, 2);

        }
    }

    void mi_Loaded(object sender, System.Windows.RoutedEventArgs e)
    {
        System.Windows.Controls.MenuItem mi = sender as System.Windows.Controls.MenuItem;
        if (mi != null && mi.Template != null)
        {
            System.Windows.Controls.ContentPresenter cp = mi.Template.FindName("Icon", mi) as System.Windows.Controls.ContentPresenter;
            cp.Height = ICON_SIZE + 6;
            cp.Width = ICON_SIZE + 6;
        }

    }