Algorithm: Max Counters

Question

I have the following problem:

You are given N counters, initially set to 0, and you have two possible operations on them:

• increase(X) − counter X is increa

Answer 1

The key is that [0] * N is an N operation. If that exists in a for loop it will become N*M. Tested in Codility 100%

            # you can write to stdout for debugging purposes, e.g.
            # print "this is a debug message"

            def solution(N, A):
                # write your code in Python 2.7
                count = [0] * N
                maxCounter = 0
                minCounter = 0
                for x in A:
                    if x <= N and x >= 1:
                        count[x-1] = max(count[x-1], minCounter) + 1
                        if maxCounter < count[x-1]:
                            maxCounter = count[x-1]
                    if x == N + 1:
                        minCounter = maxCounter                
                for i in xrange(N):
                    count[i] = max(count[i], minValue)
                return count