simple udp proxy solution

Question

I am looking for solution that can proxy my udp packets. I have one client sending udp packets to a server. Connection between them is very bad and I get lot of packet loss. One

Answer 1

Here is Python code written for this purpose:

import socket
from threading import Thread

class Proxy(Thread):
    """ used to proxy single udp connection 
    """
    BUFFER_SIZE = 4096 
    def __init__(self, listening_address, forward_address):
        print " Server started on", listening_address
        Thread.__init__(self)
        self.bind = listening_address
        self.target = forward_address

    def run(self):
        # listen for incoming connections:
        target = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
        target.connect(self.target)

        s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
        try:
            s.bind(self.bind)
        except socket.error, err:
            print "Couldn't bind server on %r" % (self.bind, )
            raise SystemExit
        while 1:
            datagram = s.recv(self.BUFFER_SIZE)
            if not datagram:
                break
            length = len(datagram)
            sent = target.send(datagram)
            if length != sent:
                print 'cannot send to %r, %r !+ %r' % (self.target, length, sent)
        s.close()


if __name__ == "__main__":
    LISTEN = ("0.0.0.0", 8008)
    TARGET = ("localhost", 5084)
    while 1:
        proxy = Proxy(LISTEN, TARGET)
        proxy.start()
        proxy.join()
        print ' [restarting] '

I used this two scripts to test it.

import socket

target = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
target.connect(("localhost", 8008))
print 'sending:', target.send("test data: 123456789")

and

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind(("localhost", 5084))
while 1:
    datagram = s.recv(1024)
    if not datagram:
        break
    print repr(datagram)

s.close()