It\'s possible to define a pointer to a member and using this later on:
struct foo
{
int a;
int b[2];
};
int main()
{
foo bar;
int foo::*
typedef int (foo::*b_member_ptr)[2];
b_member_ptr c= &foo::b;
all works.
small trick for member and function pointers usage.
try to write
char c = &foo::b; // or any other function or member pointer
and in compiller error you will see expected type, for your case int (foo::*)[2]
.
EDIT
I'm not sure that what you want is legal without this pointer. For add 1 offset to your pointer you should get pointer on array from your pointer on member array. But you can dereference member pointer without this.