I have the following code:
int *numberArray = calloc(n, sizeof(int));
And I am unable to understand why I receive the following error.
void* calloc (size_t num, size_t size);
Allocate and zero-initialize array. Allocates a block of memory for an array of num elements, each of them size bytes long, and initializes all its bits to zero.The effective result is the allocation of a zero-initialized memory block of (num*size) bytes.
On success, a pointer to the memory block allocated by the function. The type of this pointer is always void*, which can be cast to the desired type of data pointer in order to be dereferenceable. If the function failed to allocate the requested block of memory, a null pointer is returned.
To summarize, since calloc
returns a void*
(generic pointer) on success of memory allocation, you will have to type-cast it like this in C++:
int *numberArray = (int*)calloc(n, sizeof(int));
If it was C, you can still skip this cast.
Or, use new
as:
int *numberArray = new int [n];