Optionally serialize a property based on its runtime value

Question

Fundamentally, I want to include or omit a property from the generated Json based on its value at the time of serialization.

More-specifically, I have a type that knows

Answer 1

Because you are asking to do it based on the value of a property what you can do is put the data into a dictionary. You can exclude adding the value to the dictionary. Below is a simple example of how to get the data out of an object.

public class Class1
{
    public string Name { get; set; }
}

[TestFixture]
public class Tests
{
    [Test]
    public void ConvertTest()
    {
        var dictionary = new Dictionary();
        var @class = new Class1 { Name = "Joe" };

        var propertyInfos = typeof (Class1).GetProperties();

        foreach (PropertyInfo propertyInfo in propertyInfos)
        {
            dictionary.Add(propertyInfo.Name, propertyInfo.GetValue(@class, BindingFlags.GetProperty, null, null, null));
        }

        var serializeObject = JsonConvert.SerializeObject(dictionary);
        var o = JsonConvert.SerializeObject(@class);

        Console.WriteLine(serializeObject);
        Console.WriteLine(o);

        var class1 = JsonConvert.DeserializeObject(serializeObject);
        Console.WriteLine(class1.Name);
    }
}