C++ - overloading [] operator

Question

I have a template class Array:

template 
class Array {
    T TheArray[SIZE];
public:
    void Initialize() {
        for (int idx         


        

Answer 1

The operator[] overload will be selected based on the const-qualification of the object you call it on.

Array<> intArray;
intArray[1]; //calls T& operator[]

const Array<> constArray;
constArray[1]; //calls T operator[]

If you remove the const from T operator[], you get an error because the member functions cannot have the same const-qualification and parameters as there would be no way to select between them.