Python - start interactive debugger when exception would be otherwise thrown

Question

Is there any way to make a python program start an interactive debugger, like what import pdb; pdb.set_trace() instead of actually throwing an exception?

I

Answer 1

The simplest way is to wrap your entire code inside a try block like this:

if __name__ == '__main__':

    try:
        raise Exception()
    except:
        import pdb
        pdb.set_trace()

There is a more complicated solution which uses sys.excepthook to override the handling of uncaught exceptions, as described in this recipe:

## {{{ http://code.activestate.com/recipes/65287/ (r5)
# code snippet, to be included in 'sitecustomize.py'
import sys

def info(type, value, tb):
   if hasattr(sys, 'ps1') or not sys.stderr.isatty():
      # we are in interactive mode or we don't have a tty-like
      # device, so we call the default hook
      sys.__excepthook__(type, value, tb)
   else:
      import traceback, pdb
      # we are NOT in interactive mode, print the exception...
      traceback.print_exception(type, value, tb)
      print
      # ...then start the debugger in post-mortem mode.
      pdb.pm()

sys.excepthook = info
## end of http://code.activestate.com/recipes/65287/ }}}

The above code should be included in a file called sitecustomize.py inside site-packages directory, which is automatically imported by python. The debugger is only started when python is run in non-interactive mode.