I was looking at the openjdk-1.7.0_25
source code and I have seen this method:
/**
* Returns {@code true} if the specified number is a
* Not-a-Num
That method can return true for certain operations, for example:
System.out.println(Float.isNaN(0.0f / 0.0f));
System.out.println(Double.isNaN(Math.sqrt(-1)));
Basically, NaN
represents an undefined value. The value of 0.0 / 0.0
is NaN
, and Nan != NaN
. It may seem logical because Math.sqrt(-1)
also gives you NaN
.
See the javadoc of Double.NaN:
It is equivalent to the value returned by
Double.longBitsToDouble(0x7ff8000000000000L)
And then Double.longBitsToDouble():
If the argument is any value in the range
0x7ff0000000000001L
through0x7fffffffffffffffL
or in the range0xfff0000000000001L
through0xffffffffffffffffL
, the result is aNaN
. No IEEE 754 floating-point operation provided by Java can distinguish between two NaN values of the same type with different bit patterns.