how to use std::function to point to a function template

Question

#include 

int func(int x, int y)
{
    return x+y;
}

int main()
{
    typedef std::function Funcp;
    Funcp funcp = func;

             


        

Answer 1

As Erik points out, this is not possible directly. To achieve the effect you probably desire, you would have to make the code that uses the pointer a template.