How can I drop all indexes in a SQL database with one command?

Question

So, how can I drop all indexes in a SQL database with one command? I have this command that will get me all the 20 or so drop statements, but how can I run all of those drop s

Answer 1

None of the answers quite suited my needs.

I needed one that will also drop indexes that backup unique or primary constraints (except if these can't be dropped as they back up a foreign key)

DECLARE @SqlScript NVARCHAR(MAX);


SELECT @SqlScript = 
(
SELECT 
'
BEGIN TRY
'+ CASE WHEN 1 IN (i.is_primary_key, i.is_unique_constraint) THEN
 '
 ALTER TABLE ' + QUOTENAME(OBJECT_SCHEMA_NAME(i.object_id)) + '.' + QUOTENAME(t.name)  + ' DROP CONSTRAINT ' + QUOTENAME(i.name) + ';'
else
 '
 DROP INDEX ' + QUOTENAME(i.name)  + ' ON ' + QUOTENAME(OBJECT_SCHEMA_NAME(i.object_id)) + '.' + QUOTENAME(t.name)
 END+'

END TRY
BEGIN CATCH
RAISERROR(''Could not drop %s on table %s'', 0,1, ' + QUOTENAME(i.name, '''') + ', ' + QUOTENAME(t.name, '''') + ')
END CATCH
'
FROM sys.indexes i
JOIN sys.tables t ON i.object_id = t.object_id
WHERE i.type_desc IN ('CLUSTERED', 'NONCLUSTERED' )
ORDER BY t.object_id, i.index_id DESC
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)');

--Return script that will be run 
SELECT @SqlScript AS [processing-instruction(x)]
FOR XML PATH('');

EXEC (@SqlScript);