Lambda expression for multiple parameters

Question

I understand a lambda expression is in essence an inline delegate declaration to prevent the extra step

example

delegate int Square(int x)
public class          


        

Answer 1

You must understand the Func behavior, where the last parameter is always the output or result

Func<1, 2, outPut>

Func Add = (x, y) => x + y;

Func diff = (x, y) => x - y;

Func multi = (x, y) => x * y;