Python urllib2 URLError HTTP status code.

Question

I want to grab the HTTP status code once it raises a URLError exception:

I tried this but didn\'t help:

except URLError, e:
    logger.warning( \'It see         


        

Answer 1

Not sure why you are getting this error. If you are using urllib2 this should help:

import urllib2
from urllib2 import URLError

try:
    urllib2.urlopen(url)
except URLError, e:
    print e.code