Why double.TryParse(“0.0000”, out doubleValue) returns false ?

Question

I am trying to parse string \"0.0000\" with double.TryParse() but I have no idea why would it return false in this particular example. When I pass integer-like stri

Answer 1

it takes the localization settings at runtime into account... perhaps you are running this on a system where . is not the decimal point but , instead...

In your specific case I assume you want a fixed culture regardless of the system you are running on with . as the decimal point:

double.TryParse("0.0000", NumberStyles.Number, CultureInfo.CreateSpecificCulture ("en-US"), out temp)

OR

double.TryParse("0.0000", NumberStyles.Number,CultureInfo.InvariantCulture, out temp)

Some MSDN reference links:

• Double.TryParse(String, NumberStyles, IFormatProvider, Double)
• CultureInfo.CreateSpecificCulture(String)
• IFormatProvider Interface
• CultureInfo.InvariantCulture Property