Can C++11 decltype be used to create a typedef for function pointer from an existing function?

Question

Given

struct A { 
    int foo(double a, std::string& b) const;
};

I can create a member function pointer like this:

typedef         


        

Answer 1

Yes, of course:

typedef decltype(&A::foo) PFN_FOO;

You can also define type alias via using keyword (Thanks to Matthieu M.):

using PFN_FOO = decltype(&A::foo);