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问题:
I love jqGrid but sometimes things seem more complicated than they should be.
What I would like to achieve is to have a checkbox on each row so that a user can choose which rows are going to be submitted/processed.
I need, though, to block some checkboxes cause the user has no authorization on that particular row, maybe.
I've tried to set multiselect: true
and then I've tried to hide the checkbox:
loadComplete: function (data) { if (data.rows.length > 0) { for (var i = 0; i
and it works well but, still, .jqGrid('getGridParam', 'selarrrow')
give me the selected rows, even if they haven't been checked.
Is there any other way to have checkboxes which are enabled/disabled and a way to know which ones have been checked?
thanks
回答1:
I would suggest you to disable some checkboxed from the be selectable with respect of "disabled" attribute. To make full implementation you will need
- set "disabled" inside of
loadComplete
event handle - additionally prevent selection of disabled rows inside
beforeSelectRow
event handle - to have support of "select all" checkbox in the header of the multiselect column implement
onSelectAll
event handle which fix selection of disabled rows.
The corresponding demo can you see here. The most important part of the code is here:
var grid = $("#list10"), i; grid.jqGrid({ //... loadComplete: function() { // we make all even rows "protected", so that will be not selectable var cbs = $("tr.jqgrow > td > input.cbox:even", grid[0]); cbs.attr("disabled", "disabled"); }, beforeSelectRow: function(rowid, e) { var cbsdis = $("tr#"+rowid+".jqgrow > td > input.cbox:disabled", grid[0]); if (cbsdis.length === 0) { return true; // allow select the row } else { return false; // not allow select the row } }, onSelectAll: function(aRowids,status) { if (status) { // uncheck "protected" rows var cbs = $("tr.jqgrow > td > input.cbox:disabled", grid[0]); cbs.removeAttr("checked"); //modify the selarrrow parameter grid[0].p.selarrrow = grid.find("tr.jqgrow:has(td > input.cbox:checked)") .map(function() { return this.id; }) // convert to set of ids .get(); // convert to instance of Array } } );
UPDATED: Free jqGrid supports hasMultiselectCheckBox
callback, which can be used to create multiselect checkboxes not for all rows of jqGrid. One can use rowattr
to disable some rows additionally. As the result one will get the described above functionality in more simple way. It's recommended to use multiPageSelection: true
option additionally for free jqGrid with local data (datatype: "local"
or loadonce: true
). The option multiPageSelection: true
will hold the array selarrrow
on paging. It allows "pre-select" some rows by filling the corresponding ids inselarrrow
. See UPDATED part of the answer and the answer with the demo for additional information.
回答2:
Great answer from Oleg, I would also add code to deselect disabled rows, complete onSelectAll function below.
onSelectAll: function(aRowids,status) { if (status) { // uncheck "protected" rows var cbs = $("tr.jqgrow > td > input.cbox:disabled", grid[0]); cbs.removeAttr("checked"); //modify the selarrrow parameter grid[0].p.selarrrow = grid.find("tr.jqgrow:has(td > input.cbox:checked)") .map(function() { return this.id; }) // convert to set of ids .get(); // convert to instance of Array //deselect disabled rows grid.find("tr.jqgrow:has(td > input.cbox:disabled)") .attr('aria-selected', 'false') .removeClass('ui-state-highlight'); } }
回答3:
For people (like me) that end up on this answer after searching on Google, there is a very easy solution to this problem since jqGrid 4.0.0.
It's enough to add the css-class 'ui-state-disabled' to the row that you don't want to be selected. See The changelog of jqGrid 4.0.0. And you could still combine that with hiding or disabling the checkbox.
var $jqgrid = $("#jqgridselector"); //loop through all rows $(".jqgrow", $jqgrid).each(function (index, row) { var $row = $(row); if ($row === condition) { //Find the checkbox of the row and set it disabled $row.find("input:checkbox").attr("disabled", "disabled"); //add class ui-state-disabled, because thats how jqGrid knows not to take them into account for selection $row.addClass("ui-state-disabled"); //I overwrite the opactity of the ui-state-disabled class to make the row look 'normal' $row.css("opacity", 1); } });
回答4:
I've found a work-around. During the loadComplete event I disable the SelectAll checkbox: I don't need it. I also hide the checkbox and disable it.
loadComplete: function (data) { $("#cb_OrdersGrid").css("visibility", "hidden"); if (data.rows.length > 0) { for (var i = 0; i
Now, when I want to submit my data I loop through the selected rows and check if they've been disabled and put those which are enabled in a new array.
var selectedRows = myGrid.jqGrid('getGridParam', 'selarrrow'); var checkedRows = []; var selectionLoop = 0; for (var x = 0; x
What I've achieved now is to be able to select a row conditionally being able to check it or not.
I know the code is not optimized (forgive me Oleg) but I'll do it later.
回答5:
I'm using jqGrid 4.4.4 and I had to tweak LetfyX loadComplete just a little.
loadComplete: function(data) { for (var i = 0; i