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问题:
I have computed a test statistic that is distributed as a chi square with 1 degree of freedom, and want to find out what P-value this corresponds to using python.
I'm a python and maths/stats newbie so I think what I want here is the probability denisty function for the chi2 distribution from SciPy. However, when I use this like so:
from scipy import stats stats.chi2.pdf(3.84 , 1) 0.029846
However some googling and talking to some colleagues who know maths but not python have said it should be 0.05.
Any ideas? Cheers, Davy
回答1:
Quick refresher here:
Probability Density Function: think of it as a point value; how dense is the probability at a given point?
Cumulative Distribution Function: this is the mass of probability of the function up to a given point; what percentage of the distribution lies on one side of this point?
In your case, you took the PDF, for which you got the correct answer. If you try 1 - CDF:
>>> 1 - stats.chi2.cdf(3.84, 1) 0.050043521248705147
PDF CDF
回答2:
To calculate probability of null hypothesis given chisquared sum, and degrees of freedom you can also call chisqprob
:
>>> from scipy.stats import chisqprob >>> chisqprob(3.84, 1) 0.050043521248705189
Notice:
chisqprob is deprecated! stats.chisqprob is deprecated in scipy 0.17.0; use stats.distributions.chi2.sf instead
回答3:
While stats.chisqprob() and 1-stats.chi2.cdf() appear comparable for small chi-square values, for large chi-square values the former is preferable. The latter cannot provide a p-value smaller than machine epsilon,and will give very inaccurate answers close to machine epsilon. As shown by others, comparable values result for small chi-squared values with the two methods:
>>>from scipy.stats import chisqprob, chi2 >>>chisqprob(3.84,1) 0.050043521248705189 >>>1 - chi2.cdf(3.84,1) 0.050043521248705147
Using 1-chi2.cdf() breaks down here:
>>>1 - chi2.cdf(67,1) 2.2204460492503131e-16 >>>1 - chi2.cdf(68,1) 1.1102230246251565e-16 >>>1 - chi2.cdf(69,1) 1.1102230246251565e-16 >>>1 - chi2.cdf(70,1) 0.0
Whereas chisqprob() gives you accurate results for a much larger range of chi-square values, producing p-values nearly as small as the smallest float greater than zero, until it too underflows:
>>>chisqprob(67,1) 2.7150713219425247e-16 >>>chisqprob(68,1) 1.6349553217245471e-16 >>>chisqprob(69,1) 9.8463440314253303e-17 >>>chisqprob(70,1) 5.9304458500824782e-17 >>>chisqprob(500,1) 9.505397766554137e-111 >>>chisqprob(1000,1) 1.7958327848007363e-219 >>>chisqprob(1424,1) 1.2799986253099803e-311 >>>chisqprob(1425,1) 0.0
Update: as noted, chisqprob() is deprecated for scipy version 0.17.0 onwards. High accuracy chi-square values can now be obtained via scipy.stats.distributions.chi2.sf(), for example:
>>>from scipy.stats.distributions import chi2 >>>chi2.sf(3.84,1) 0.050043521248705189 >>>chi2.sf(1424,1) 1.2799986253099803e-311
回答4:
You meant to do:
>>> 1 - stats.chi2.cdf(3.84, 1) 0.050043521248705147
回答5:
Some of the other solutions are deprecated. Use scipy.stats.chi2
Survival Function. Which is the same as 1 - cdf(chi_statistic, df)
Example:
from scipy.stats import chi2 p_value = chi2.sf(chi_statistic, df)
回答6:
If you want to understand the math, the p-value of a sample, x (fixed), is
P[P(X) <= P(x)] = P[m(X) >= m(x)] = 1 - G(m(x)^2)
where,
- P is the probability of a (say k-variate) normal distribution w/ known covariance (cov) and mean,
- X is a random variable from that normal distribution,
- m(x) is the mahalanobis distance = sqrt( < cov^{-1} (x-mean), x-mean >. Note that in 1-d this is just the absolute value of the z-score.
- G is the CDF of the chi^2 distribution w/ k degrees of freedom.
So if you're computing the p-value of a fixed observation, x, then you compute m(x) (generalized z-score), and 1-G(m(x)^2).
for example, it's well known that if x is sampled from a univariate (k = 1) normal distribution and has z-score = 2 (it's 2 standard deviations from the mean), then the p-value is about .046 (see a z-score table)
In [7]: from scipy.stats import chi2 In [8]: k = 1 In [9]: z = 2 In [10]: 1-chi2.cdf(z**2, k) Out[10]: 0.045500263896358528